If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2-9=6x^2-59
We move all terms to the left:
4x^2-9-(6x^2-59)=0
We get rid of parentheses
4x^2-6x^2+59-9=0
We add all the numbers together, and all the variables
-2x^2+50=0
a = -2; b = 0; c = +50;
Δ = b2-4ac
Δ = 02-4·(-2)·50
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*-2}=\frac{-20}{-4} =+5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*-2}=\frac{20}{-4} =-5 $
| 3-(4w+6)=(8w+28) | | 4x-7x=6-15 | | 7x-1=7+1 | | 3^2b=5^-b+1 | | 65z −12=612−2z | | 3x-(5x-10)=-6 | | 5d-6d=4 | | -4(x+5)-2=2 | | 3(2x+5)=-4(3x-5) | | 9/12=v/8v= | | 3/9=w/12w= | | x|5=25 | | √t=10 | | 0.10x=5.00 | | 5x−16=−6 | | 0.05x=5.00 | | 9x^2+2x+14=0 | | -21=33x | | 3f+9f=24 | | 3r-3=33 | | (x+5)(x+2)-3(4x-3)=(x-5)^2 | | 4+7/3x=-4+1/4x | | 20=-5(4+x) | | 4+7-3x=-4+1/4x | | 4(3x+6)-24=x | | 4+7n=4 | | 2x–7=23 | | 2x–7=23. | | -30=p-15 | | (X-5)^2+5=x | | 4(x-2)-2x=19 | | 9-9x=7-8x |